In fig. 9.3 if ∠aob 125° then ∠cod is equal t
WebThe chapter 9, Triangles, contains 2 exercises and the Solutions given here contains the answers for all the questions present in these exercises. Let us have a look at some of the topics that are being discussed in this chapter. 9.1 Introduction. 9.2 Relation between sides and angles of triangles. WebIn Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to a. 62.5°, b. 45°, c. 35°, d. 55° In Fig. 9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the . . . . From a point P which is at a distance of 13 cm from the centre O of a circle of radius 5 cm, the pai . . . . Explore math program
In fig. 9.3 if ∠aob 125° then ∠cod is equal t
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WebAnswer: Let O be the centre of two concentric circles C 1 and C 2 , whose radii are r 1 = 4 cm and r 2 = 5 cm. Now, we draw a chord AC of circle C 2 which is tangent to circle C 1 at B. Also, join OB, which is perpendicular to AC. So ∆ OBC is a right-angled triangle ∴ (OB) 2 + (BC) 2 = (OC) 2 (Pythagoras theorem) (4) 2 + (BC) 2 = (5) 2 WebIn Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to a. 62.5° b. 45° c. 35° d. 55° Solution: Given, ∠AOB = 125° We have to find the measure of angle COD. From the figure, We …
WebAug 24, 2024 · In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45° (C) 35° (D) 55° circles ncert class-10 Please log in or register to answer this question. 1 Answer +1 vote answered Aug 24, 2024 by BharatLal (28.2k points) Correct answer is (D) 55° ← Prev Question Next Question → Find MCQs & Mock Test Free JEE Main Mock Test Free NEET … WebMay 16, 2024 · In figure, chords AB and CD of circle with center O, arc same. If ∠AOB = 55°, then ∠COD will be : (A) 110° (B) 75° (C) 90° (D) 55° circle class-10 1 Answer +1 vote answered May 16, 2024 by VinodeYadav (35.7k points) selected May 17, 2024 by HarshKumar Best answer Answer is (D) 55° Chord AB = Chord CD ˆAB A B ^ = ˆC D C D ^ …
WebIn figure, if ∠AOB = 125°, then ∠COD is equal to (a) 62.5° (b) 45° (c) 35° (d) 55° Solution: (d) We know that, the opposite sides of a quadrilateral circumscribing a circle subtend … WebIn the given figure, if ∠AOB=125 ∘, then ∠COD is equal to : A 62.5 ∘ B 45 ∘ C 125 ∘ D 55 ∘ Easy Solution Verified by Toppr Correct option is D) Opposite sides of a quadrilateral …
WebExample 10. Draw an angle equal to the difference of two angles given in Fig. 9.5. Solution: 1. Draw an angle ABC equal to ∠DEF (as ∠DEF > ∠PQR), using ruler and compasses. 2. With BC as one of the arms, draw an angle SBC equal to ∠PQR such that BS is in the interior of ∠ABC as shown in Fig. 9.6. Then, ∠ABS is the required
WebIf radii of two concentric circles are 4 cm and 5 cm, then the length of each chord of one circle wh . . . . In Fig. 9.3, if ∠AOB = 125°, then ∠COD is equal to a. 62.5°, b. 45°, c. 35°, d. 55° In Fig. 9.4, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the . . . . Explore math program fahlbtharz button puzzleWebIn the figure, given below, ABCD is a cyclic quadrilateral in which ∠BAD = 75°; ∠ABD = 58° and ∠ADC = 77°. Find: ∠BDC ∠BCD ∠BCA. VIEW SOLUTION Exercise 17 (A) Q 11 Page 258 In the following figure, O is centre of the circle and ΔABC is equilateral. Find: (i) ∠ADB, (ii) ∠AEB. VIEW SOLUTION Exercise 17 (A) Q 12 Page 258 fahlanruk the series 1.részWebDec 14, 2024 · In the given figure, if ∠AOB=125∘, then ∠COD is equal to: (A) 62.5∘ (B) 45∘ (C) 35∘ (D) 55∘ ... After some time, the angle of elevation reduces to 3 0 ∘ (see Fig. 9.13). Find the distance travelled by the balloon during the interval. 15. … fa. hinz kölnWebIn Fig. 9.3, if AOB = 125°, then COD is equal to CBSE Circles Class 10 Exercise 9.1 Maths NCERT Exemplar In Fig. 9.3, if AOB = 125°, then COD is equal to (A) 62.5° (B) 45° … fa hinz kölnWebNov 17, 2014 · EXPERTS, PLEASE ANSWER THIS AS SOON AS POSSIBLE If APB and CQD are two parallel lines then find the type of quadrilateral formed by the bisectors of the … fahlbratz puzzlehirak bewegungWebOct 28, 2024 · Here is your answer: The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center. ABCD will meet at a point where it won't … fahl badminton konz